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-20x^2-13x+2=0
a = -20; b = -13; c = +2;
Δ = b2-4ac
Δ = -132-4·(-20)·2
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{329}}{2*-20}=\frac{13-\sqrt{329}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{329}}{2*-20}=\frac{13+\sqrt{329}}{-40} $
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